1/5x^2-4x+20=0

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Solution for 1/5x^2-4x+20=0 equation: 


x in (-oo:+oo)

(1/5)*x^2-(4*x)+20 = 0

(1/5)*x^2-4*x+20 = 0

1/5*x^2-4*x+20 = 0

DELTA = (-4)^2-(1/5*4*20)

DELTA = 0

x = 4/(1/5*2)

x = 10 or x = 10

x in { 10, 10 }

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